5-9m/((m^2)-16)

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Solution for 5-9m/((m^2)-16) equation:


D( m )

m^2-16 = 0

m^2-16 = 0

m^2-16 = 0

1*m^2 = 16 // : 1

m^2 = 16

m^2 = 16 // ^ 1/2

abs(m) = 4

m = 4 or m = -4

m in (-oo:-4) U (-4:4) U (4:+oo)

5-((9*m)/(m^2-16)) = 0

5-9*m*(m^2-16)^-1 = 0

(-9*m)/(m^2-16)+5 = 0

(-9*m)/(m^2-16)+(5*(m^2-16))/(m^2-16) = 0

5*(m^2-16)-9*m = 0

5*m^2-9*m-80 = 0

5*m^2-9*m-80 = 0

5*m^2-9*m-80 = 0

DELTA = (-9)^2-(-80*4*5)

DELTA = 1681

DELTA > 0

m = (1681^(1/2)+9)/(2*5) or m = (9-1681^(1/2))/(2*5)

m = 5 or m = -16/5

(m+16/5)*(m-5) = 0

((m+16/5)*(m-5))/(m^2-16) = 0

((m+16/5)*(m-5))/(m^2-16) = 0 // * m^2-16

(m+16/5)*(m-5) = 0

( m+16/5 )

m+16/5 = 0 // - 16/5

m = -16/5

( m-5 )

m-5 = 0 // + 5

m = 5

m in { -16/5, 5 }

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